Question

What is the standard form of `y= 2x(4x-2)(x-4)-x+2`?

Answer 1

Please look below.

Explanation:

First step is two expand the brackets:

`y = 2x(4x - 2)(x-4) -x + 2`

`y = (8x^2 - 4x)(x-4) -x+2`

`y = (8x^3 - 32x^2 - 16x^2 +16x) - x + 2`

Then simplify:

`y = 8x^3 - 48x^2+ 15 x + 2`