How do you multiply #4/7*2/3#?

1 Answer
Jim G.
Apr 11, 2018

#8/21#

Explanation:

#"since there is no "color(blue)"cancelling"" of any factors"#
#"on the numerator/denominator"#

#"multiply the numbers on the numerators together and"#
#"multiply the numbers on the denominators together"#

#rArr4/7xx2/3=(4xx2)/(7xx3)=8/21#

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