How do you solve the system of equations #-x - y = 12# and #3x - y = - 12#?

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Answer 1 · 2018-04-12T03:26:54

#x=-6=>y=-6#

You can use the substitution method for this one.

Let’s call,
#-x-y=12# equation #(1)# and
#3x-y=-12# equation #(2)#

From #(1)#: #-y=x+12#

Now, substitute #-y=x+12# into #(2)#,

#3x+(x+12)=-12#

#4x=-24#

#x=-6=>y=-6# by substituting #x=-6# back into equation #(1)# or #(2)#