How do you solve #(w+8)/3-(w-8)/49=1#?

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Answer 1 · 2018-04-12T04:10:54

#w=-269/46#

#(w+8)/3-(w-8)/49=1?#

FIRST WE HAVE TO TAKE LCM OF 3 AND 49

#49 (w+8)/(3*49)-3 (w-8)/(49*3)=1#

Use the distributive property.

#(49w+392)/147-(3w-24)/147=1#

Combine the fractions with like denominators.

#(49w+392-3w+24)/147=1#

Multiply both sides of the equation by 147 and combine like terms.

#46w+416=1*147#

Simplify.

#46w+416=147#

Subtract 416 from both sides of the equation and divide both sides of the equation by 46.

#w=(147-416)/46#

Simplify.

#w=-269/46#