How to simplify #(3times10^8)/(6times10^ -7)# in scientific notation?

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Answer 1 · 2018-04-12T09:05:35

Keeping the solution in the same format as the question:

#5.0xx10^14#

#color(brown)("They are testing your observation with this one.")#

#color(brown)("Note that "1/10^(-7)" is the same as "10^7#
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Write as: #(cancel(3)^1xx10^8xx10^7)/cancel(6)^2 = 10^(15)/2 = 1/2xx10^15#

but #1/2 = 0.5#

#0.5xx10^15#

#5.0xx10^14#

Answer 2 · 2018-04-12T09:06:18

#5xx10^15#

Deal with the whole numbers#=># #3/6=#0.5

When dividing like terms with powers we simply subtract the

powers #=># #10^8/(10^-7)#. #=>#8-(-7) = 8+7= 15

#10^8/(10^-7)# =#10^15#

#(3xx10^8)/(6xx10^(-7))# = #0.5xx10^15#

This is 5 with 14 zeros after it 500,000,000,000,000

In scientific form #5xx10^15#