Question

What is the vertex of `9y= 3(x+5)^2 +12`?

Answer 1

Vertex is at `(-5,4/3)`

Explanation:

`9y=3(x+5)^2+12` or

`y=1/3(x+5)^2+4/3` . Comparing with vertex form of

equation `f(x) = a(x-h)^2+k ; (h,k)` being vertex we find

here `h=-5 , k=4/3 :.` Vertex is at `(-5,4/3)`

graph{9y=3(x+5)^2+12 [-10, 10, -5, 5]}