Question

How do you evaluate `(7^ { 3/ 4} ) ^ { - 2/ 9}`?

Answer 1

`=> (7)^(-1/6)`

Explanation:

As per Laws of Indices,

`(a^m)^n) = a ^(m * n)`

`(7^(3/4))^-(2/9) = (7)^((3/4) * (-2/9))`

`=> (7)^(-6/36) = (7)^(-1/6)`

`(7)^(-1/6)` can be rewritten as `.^6sqrt(1/7)`.

I hope that helps!