Question

What is the derivative of `y=csc(x/2)`?

Answer 1

-`1/2` `csc(x/2)cot(x/2)`

Explanation:

given

`y=cec(x/2)`
we know that
derivative of csc(x)=-csc(x)cot(x)
derivative of ( `x/n` )= `1/n`

from this `dy/dx`=- `1/2csc(x/2)cot(x/2)`