How do you simplify #4i(-2-8i)#?

1 Answer
angie c
Apr 15, 2018

The answer is #-8i+32#.

Explanation:

Simplifying #4i(-2-8i)#:

First, factor out the #4i#: #-8i-32i^2#.

Because #i#, an imaginary number, is equal to #sqrt(-1)#, #i^2# (or #(sqrt(-1))^2# should be #-1#.

Therefore, you can substitute in #-1# for #i^2#. Therefore your answer is #-8i-(32*-1)#. This simplifies to your final answer, #-8i+32#.

Hope this helps!

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