How do you differentiate #f(x)=ln2x * sin3x# using the product rule? Calculus Basic Differentiation Rules Product Rule 1 Answer Sahar Mulla ❤ Apr 15, 2018 #f(x)=ln2x * sin3x# Applying product rule, When, #f(x)=g(x)*h(x)# #f'(x)=g'(x)h(x)+g(x)h'(x)# #=>f'(x)=(ln2x)' sin3x+ln2x (sin3x)'# #=>f'(x)=[1/(2x)xx2xxsin3x]+[ln2x xxcos3x xx3]# #=>f'(x)=1/xsin3x+3ln2xcos3x# Answer link Related questions What is the Product Rule for derivatives? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x - 3)(2 - 3x)(5 - x)# ? How do you use the product rule to find the derivative of #y=x^2*sin(x)# ? How do you use the product rule to differentiate #y=cos(x)*sin(x)# ? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x^4 +x)*e^x*tan(x)# ? How do you use the product rule to find the derivative of #y=(x^3+2x)*e^x# ? How do you use the product rule to find the derivative of #y=sqrt(x)*cos(x)# ? How do you use the product rule to find the derivative of #y=(1/x^2-3/x^4)*(x+5x^3)# ? How do you use the product rule to find the derivative of #y=sqrt(x)*e^x# ? How do you use the product rule to find the derivative of #y=x*ln(x)# ? See all questions in Product Rule Impact of this question 1907 views around the world You can reuse this answer Creative Commons License