Question

How do you use cross products to solve `2/9=c/27`?

Answer 1

Just arrange the equation

Explanation:

`2/9 = c/27`

`2times27 = ctimes9`

`(2times27)/9 = c`

`2times3=c`

`6=c`

Answer 2

c = 6

Explanation:

First we need to cross multiply.
`2 xx 27 = 9 xx c`

Which gives us...
`54 = 9c`

To make the next step easy, we will flip the equation
`9c = 54`

Now we can find the value of c
`c = 54 / 9`

`c = 6`

Answer 3

`c=6`

Explanation:

`"given equal fractions then we can solve using "color(blue)"cross-products"`

`"that is "a/b=c/drArrbc=adlarrcolor(blue)"cross-products"`

`"applying this to "2/9=c/27" gives"`

`9c=2xx27`

`rArr9c=54`

`"divide both sides by 9"`

`(cancel(9) c)/cancel(9)=54/9`

`rArrc=6`