How do you simplify #sectheta/sintheta(1-cos^2theta)#?

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Answer 1 · 2018-04-16T09:33:14

The answer is #=tantheta#

We need

#sin^2theta+cos^2theta=1#

#sectheta=1/costheta#

#tantheta=sintheta/costheta#

Therefore,

#sectheta/sintheta(1-cos^2theta)=sectheta/sintheta*sin^2theta#

#=1/costheta*sintheta#

#=tantheta#

Answer 2 · 2018-04-16T09:33:48

# tantheta#.

#sectheta/sintheta(1-cos^2theta)#,

#=sectheta/sintheta*sin^2theta#,

#=sectheta*sintheta#,

#=1/costheta*sintheta#,

#=sintheta/costheta#,

#=tantheta#.