Write 2x-7y+12=0 in polar form?

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Answer 1 · 2018-04-18T23:23:47

#r=-12/(2cos(theta)-7sin(theta))#

Remember that:

#x=rcos(theta)#

#y=rsin(theta)#

We substitute:

#2*rcos(theta)-7*rsin(theta)+12=0#

#=>r(2cos(theta)-7sin(theta))+12=0#

#=>r(2cos(theta)-7sin(theta))=-12#

#=>r=-12/(2cos(theta)-7sin(theta))#

That is the answer!