How do I find #sintheta# = #-cos^2theta# -1 in radians from #[0, 2pi]#?
How do I find #sintheta# = #-cos^2theta# -1 in radians from #[0, 2pi]# ?
How do I find
3 Answers
Explanation:
Since
(note that
Explanation:
We can get this equation in terms of one trigonometric function using trig identities. In this case, we know the identity
So, we apply it to the right side:
Move everything to the right. This gives us the following:
Or,
This strongly resembles a quadratic equation; however, instead of
As a result, we can factor this just as we would factor a quadratic:
We then solve the following:
For
Tells us this one has no solutions, as
Holds true for
Explanation:
We can use one of the Pythagorean identities to write our equation in terms of a single trigonometric function. In particular, we can use:
We get:
We'll solve as follows.
The product of the factors
So if the equation has a solution, at least one of the factors must be zero.
or
Sine has the value
It NEVER has the value