What is the standard form of #y= (3x+1/2x^2)(6x-2) #? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer sankarankalyanam Apr 19, 2018 #color(green)("Standard form is " y = 3x^3 + 17x^2 - 6x# Explanation: #y = (3x + x^2/2) * ( 6x - 2)# #=> 18x^2 + 3x^3 - 6x - x^2# #color(green)("Standard form is " y = 3x^3 + 17x^2 - 6x# Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is #x^2+3x^{\frac{1}{2}}# a polynomial? How do you express #-16+5f^8-7f^3# in standard form? What is the degree of #16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2#? What is the degree of the polynomial #x^4-3x^3y^2+8x-12#? What is the difference between a monomial, binomial and polynomial? How do you write #y = 2/3x + 5# in standard form? See all questions in Polynomials in Standard Form Impact of this question 1541 views around the world You can reuse this answer Creative Commons License