How do you find the derivative of #arcsin(3x)#?
1 Answer
Apr 19, 2018
Explanation:
#"differentiate using the "color(blue)"chain rule"#
#"Given "y=f(g(x))" then"#
#dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"#
#rArrd/dx(arcsin(3x))=1/sqrt(1-(3x)^2)xxd/dx(3x)#
#color(white)(xxxxxxxxxxxxx)=3/sqrt(1-9x^2)#