How do you solve $2 = \frac{n}{2} - 3$ $2= \frac { n } { 2} - 3$ ?

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Answer 1 · 2018-04-20T04:34:53

$n = 10$ $n=10$

Order of operations is a little backwards when solving an equation that has two sides, so:

$2 = \frac{n}{2} - 3$ $2=n/2 -3$

$2 color(blue)(+3)=n/2 cancel(-3)color(blue)(cancel(+3))$ $color(blue)(" | Add 3 to both sides to get rid of the "-3)$

$5=n/2$

$5 color(blue)(*2)=n/cancel(2) color(blue)(cancel(*2))$ $color(blue)("| Multiplying both sides by " 2 " cancels fraction")$

$n=10$

Let's double check:

$2=10/2 - 3$

$2=5-3$ $color(blue)(" | "10/2=5)$

$2=2$ $color(blue)(" | "5-3=2 " True")$

How do you solve 2= \frac { n } { 2} - 32=n2−32= \frac { n } { 2} - 3?