Question

What is the equation of the parabola that has a vertex at `(0, 0)` and passes through point `(-1,-64)`?

Answer 1

`f(x)=-64x^2`

Explanation:

If the vertex is at (0|0),
`f(x)=ax^2`
Now, we just sub in the point `(-1,-64)`

`-64=a*(-1)^2=a`
`a=-64`
`f(x)=-64x^2`