How do you write ((10+4i)-(3-2i))/((6-7i)(1-2i)) in standard form?

1 Answer
Apr 21, 2018

(10+4i-(3-2i))/((6-7i)(1-2i))=-2/5+i/5

Explanation:

(10+4i-(3-2i))/((6-7i)(1-2i))

Simplify numerator and multiply out denominator

(7+6i)/(-8-19i)

Multiply the numerator and denominator by the complex conjugate of the denominator.

((7+6i)(-8+19i))/((-8-19i)(-8+19i))

Apply the distributive property to the numerator and denominator.

(-170+85i)/425

Factor out the common factor.

(85(-2+i))/(85(5))

Simplify.

(-2+i)/5=-2/5+i/5