How do you write an equation of a line passing through (-16, -11), perpendicular to y = -4x -2?
1 Answer
Apr 22, 2018
Explanation:
"the equation of a line in "color(blue)"slope-intercept form" is.
•color(white)(x)y=mx+b
"where m is the slope and b the y-intercept"
y=-4x-2" is in this form"
"with "m=-4
"given a line with slope m then the slope of a line"
"perpendicular to it is"
•color(white)(x)m_(color(red)"perpendicular")=-1/m
rArrm_("perpendicular")=-1/(-4)=1/4
rArry=1/4x+blarrcolor(blue)"is the partial equation"
"to find b substitute "(-16,-11)" into the partial equation"
-11=-4+brArrb=-11+4=-7
rArry=1/4x-7larrcolor(red)"perpendicular equation"