How do you write an equation of a line passing through (-16, -11), perpendicular to y = -4x -2?

1 Answer
Apr 22, 2018

y=1/4x-7

Explanation:

"the equation of a line in "color(blue)"slope-intercept form" is.

•color(white)(x)y=mx+b

"where m is the slope and b the y-intercept"

y=-4x-2" is in this form"

"with "m=-4

"given a line with slope m then the slope of a line"
"perpendicular to it is"

•color(white)(x)m_(color(red)"perpendicular")=-1/m

rArrm_("perpendicular")=-1/(-4)=1/4

rArry=1/4x+blarrcolor(blue)"is the partial equation"

"to find b substitute "(-16,-11)" into the partial equation"

-11=-4+brArrb=-11+4=-7

rArry=1/4x-7larrcolor(red)"perpendicular equation"