How do you write an equation of a line passing through (-16, -11), perpendicular to #y = -4x -2#?
1 Answer
Apr 22, 2018
Explanation:
#"the equation of a line in "color(blue)"slope-intercept form"# is.
#•color(white)(x)y=mx+b#
#"where m is the slope and b the y-intercept"#
#y=-4x-2" is in this form"#
#"with "m=-4#
#"given a line with slope m then the slope of a line"#
#"perpendicular to it is"#
#•color(white)(x)m_(color(red)"perpendicular")=-1/m#
#rArrm_("perpendicular")=-1/(-4)=1/4#
#rArry=1/4x+blarrcolor(blue)"is the partial equation"#
#"to find b substitute "(-16,-11)" into the partial equation"#
#-11=-4+brArrb=-11+4=-7#
#rArry=1/4x-7larrcolor(red)"perpendicular equation"#