How to do this?

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1 Answer
Apr 23, 2018

See the answer below...

Explanation:

#" "3-2sin^2theta=sin theta+3#

#=>cancel3-2sin^2theta=sintheta+cancel3#

#=>sintheta+2sin^2theta=0#

#=>sintheta cdot(2sintheta+1)=0#

Either,

#sintheta=0" "" "(2sintheta+1)=0#

#=>color(red)(ul(bar(|color(blue)(theta=npi))|)" "=>sintheta=-1/2#

#" "=>color(red)(ul(bar(|color(blue)(theta=npi-(-1)^n cdot pi/6))|#

Note:-#n in I#

Hope it helps...
Thank you...

:-)