How do you solve #2(4y-1)=18#?

1 Answer
Jim G.
Apr 24, 2018

#y=5/2#

Explanation:

#"distribute parenthesis on left side of equation"#

#8y-2=18#

#"add 2 to both sides"#

#8ycancel(-2)cancel(+2)=18+2#

#rArr8y=20#

#"divide both sides by 8"#

#(cancel(8) y)/cancel(8)=20/8#

#rArry=cancel(20)^5/cancel(8)^2=5/2#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#2((4xx5/2)-1)=2(10-1)=18="right side"#

#rArry=5/2" is the solution"#

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