How do you solve #|5s + 1| = | s - 3|#?

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Answer 1 · 2018-04-24T11:27:22

Solution : #s=-1 , s= 1/3#

#|5 s+1| = |s-3|# . Squaring both sides we get,

#(5 s+1)^2 = (s-3)^2# or

#25 s^2+10 s+1 = s^2-6 s +9# or

#25 s^2+10 s+1 - s^2 +6 s -9 = 0# or

#24 s^2 + 16 s -8=0# or

#3 s^2 + 2 s -1=0 # or

#3 s^2 + 3 s - s-1=0 # or

#3 s(s+1) -1( s+1)=0 # or

#(s+1)(3 s -1)=0 :. # either #s+1=0 :. s = -1# or

#(3 s -1)=0 :. s = 1/3#

Solution : #s=-1 , s= 1/3# [Ans]