Given that tan #2pi//9=0.8391#, use equivalent trigonometric expressions to evaluate cot #5pi//18#, to four decimal places?

2 Answers
Apr 24, 2018

#cot((5pi)/18)=0.8391#

Explanation:

#tan((2pi)/9)=0.8391#

#cot(pi/2 - Theta)=tan(Theta)#
#:.#
#cot((5pi)/18)=cot(pi/2 - (2pi)/9)=tan((2pi)/9)=0.8391#

Apr 24, 2018

#0.8391#

Explanation:

#cot((5pi)/18)=cot((2pi)/9+pi/18)#

#color(green)(tan(a+b)=(tana+tanb)/(1-tana*tanb)#

#=1/(tan((2pi)/9+pi/18))=(1-tan((2pi)/9)*tan(pi/18))/(tan((2pi)/9)+tan(pi/18)#

#tan(pi/18)=0.17633#

#=(1-0.8391*0.17633)/(0.8391+0.17633)=0.8391#