How do you simplify #(x^2 +5x -6)/(x+6)#?

1 Answer
Apr 24, 2018

#x-1#

Explanation:

Let's try to factor the numerator, #x^2+5x-6# first. What two numbers sum up to #5# and those same two multiply to get #-6#?

Their product is negative, so the signs must be different. After some thought, we arrive at #-1# and #6#. Thus, we have:

#((x-1)(x+6))/(x+6)#

#=>((x-1)cancel(x+6))/cancel(x+6)#

#=>x-1#

Hope this helps!