Question

A swimmer speeds up from 1.1 m/s to 1.3 m/s during the last 20 s of a workout. What is the swimmer's acceleration during this time interval?

Answer 1

`a = 0.01 m/s^2`

Explanation:

From this equation of motion

`v = u + a*t`, we can use algebra to solve for a and write

`a = (v-u)/t`

Plugging our data into that last equation

`a = (1.3 m/s - 1.1 m/s)/t = (0.2 m/s)/(20 s) = 0.01 m/s^2`

I hope this helps,
Steve