How do you find the derivative of #y=tan^2(5x)#?

1 Answer
Jim G.
Apr 25, 2018

#dy/dx=10tan5xsec^2 5x#

Explanation:

#"differentiate using the "color(blue)"chain rule"#

#"Given "y=f(g(x))" then"#

#dy/dx=f'(g(x))xxg'(x)#

#y=tan^2 5x=(tan5x)^2#

#rArrdy/dx=2tan5x xxd/dx(tan5x)#

#color(white)(rArrdy/dx)=2tan5x xxsec^2 5x xxd/dx(5x)#

#color(white)(rArrdy/dx)=10tan5xsec^2 5x#

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