How do you add #5sqrt48-4sqrt75#?

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Answer 1 · 2018-04-26T19:25:23

#5sqrt{48} - 4sqrt{75}= 0#

First, attempt to simplify the radicals.

#5sqrt{48} - 4sqrt{75}#

#5sqrt{6 times 8} - 4sqrt{15 times 5}#

#5sqrt{2^4 times 3} - 4sqrt{3 times 5^2}#

The squares can be factored out.

#5 times 2^2sqrt{3} - 5 times 4sqrt{3}#

This can now be simplified:

#(5 times 2^2- 5 times 4) times sqrt{3}#

#(20- 20) times sqrt{3}#

#(0) times sqrt{3}= 0#