Question

15x+3y=33 what is y?

Answer 1

`y=-5x+11`

Explanation:

Since there are 2 variables, we cannot solve for `y` and get a definite number, but we can isolate `y` and solve for it in terms of `x`:

`15x+3y=33`

`3y=33-15x`

`y=11-5x`

`y=-5x+11`

Answer 2

`y = 11 - 5x`

Explanation:

`15x + 3y = 33`

To find `y`, we have to make `y` alone. To do so, let's put everything else on the other side of the equation.

First, subtract `color(red)(15x)` from both sides of the equation:
`15x + 3y quadcolor(red)(-quad15x) = 33 quadcolor(red)(-quad15x)`

`3y = 33 - 15x`

Now divide both sides by `3` to get `y` by itself:
`(3y)/color(red)(3) = (33-15x)/color(red)(3)`

Therefore:
`y = (33-15x)/3`

This can still be simplified since both `33` and `-15x` are divisible by `3`. So the final answer is:
`y = 11 - 5x`

Hope this helps!