What is the moment of inertia of a pendulum with a mass of #5 kg# that is #11m# from the pivot?

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Answer 1 · 2018-04-27T07:07:42

#605 \ "kg m"^2#

Moment of inertia #(I)# of a simple pendulum is given by:

#I=mr^2#

#m# is the mass of the pendulum bob

#r# is the distance of the pendulum from the pivot

So, inputting our given values, we get:

#I=5 \ "kg"*(11 \ "m")^2#

#=5 \ "kg"*121 \ "m"^2#

#=605 \ "kg m"^2#