How do you condense #log r- log t- 2log s#?
1 Answer
Apr 27, 2018
Explanation:
#"using the "color(blue)"laws of logarithms"#
#•color(white)(x)logx+logyhArrlog(xy)#
#•color(white)(x)logx-logyhArrlog(x/y)#
#•color(white)(x)logx^nhArrnlogx#
#rArrrlogr-(logt+logs^2)#
#=logr-log(ts^2)#
#=log(r/(ts^2))#