A charge of #16 C# passes through a circuit every #12 s#. If the circuit can generate #36 W# of power, what is the circuit's resistance?

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Answer 1 · 2018-04-27T13:42:24

The circuit resistance is #=20.25Omega#

Apply the equation

#"Charge"(C)"# #= "Current(A)"xx"time (t)"#

The charge is #Q=16C#

The time is #t=12s#

The current is #I=16/12=4/3A#

Ohm's Law states that

#U=RI#

The power is

#P=UI=RI^2#

The power is #P=36W#

The resistance is

#R=P/(I^2)=36/(4/3)^2=20.25Omega#