Question

If I have 186 moles of Hydrogen and 86 moles of Oxygen, how many moles of water can I make?

I forgot how to set up this equation. I have the reactants, but I need to find how much product I can make.

Answer 1

`172" mol H"_2O`

Explanation:

Let's write a balanced stoichometric equation:
`2H_2+O_2= 2H_2O`

We need to know what is the limiting reagent, so we must compare molar ratios:

`86 mol O_2*(2 "mol H"_2)/(1 " mol O"_2)= 172" mols H"_2 "needed"`

Since more than that amount H_2 is available it is in excess, we will use O_2 which is the limiting reagent to determine how much water we can make

`86 " mol O"_2*(2 "mol H"_2"O")/(1 " mol O"_2)= 172 mols H_2O`