If a rocket with a mass of 3900 tons vertically accelerates at a rate of # 7/9 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 5 seconds?

1 Answer
Udhaya S.
Apr 28, 2018

#P = Fv#
#v# at #5# seconds, #7/9 * 5 = 35/9ms^-1#
#sumF = ma#
#sumF = 3900*1000 * 7/9#
#sumF = 3.03#x#10^6#
Force upwards = #3.03#x#10^6# + #3900000*9.81#=#4.13#x#10^7# N
#P = 4.13^10^7 * 35/9#
#P = 1.61#x#10^8##W#

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