What is the derivative of #y=x (4-x)^.5#? Calculus Basic Differentiation Rules Product Rule 1 Answer mizoo Apr 28, 2018 #dy/dx = (8 - 3x)/(2sqrt(4-x)) # Explanation: #dy/dx = 1 xx (4 - x)^(0.5) + 0.5(4 - x)^(0.5-1) (-1) xx x# #dy/dx = (4 - x)^(0.5) - (0.5x)/(4 - x)^0.5 # #dy/dx = (8 - 3x)/(2sqrt(4-x)) # Answer link Related questions What is the Product Rule for derivatives? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x - 3)(2 - 3x)(5 - x)# ? How do you use the product rule to find the derivative of #y=x^2*sin(x)# ? How do you use the product rule to differentiate #y=cos(x)*sin(x)# ? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x^4 +x)*e^x*tan(x)# ? How do you use the product rule to find the derivative of #y=(x^3+2x)*e^x# ? How do you use the product rule to find the derivative of #y=sqrt(x)*cos(x)# ? How do you use the product rule to find the derivative of #y=(1/x^2-3/x^4)*(x+5x^3)# ? How do you use the product rule to find the derivative of #y=sqrt(x)*e^x# ? How do you use the product rule to find the derivative of #y=x*ln(x)# ? See all questions in Product Rule Impact of this question 1618 views around the world You can reuse this answer Creative Commons License