How do you solve: cot(-x)cos(-x)+sin(-x) ?

1 Answer
Apr 28, 2018

Please see below.

Explanation:

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If you meant "how do you simplify this:

#cot(-x)cos(-x)+sin(-x)=cos(-x)/sin(-x)*cos(-x)+sin(-x)=cos^2(-x)/sin(-x)+sin(-x)=(cos^2(-x)+sin^2(-x))/sin(-x)=1/sin(-x)=1/(-sinx)=-cscx#

If you meant to solve for #x# by setting the expression equal to #0#:

#-cscx=0, :. -1/sinx=0, :. sinx=oo# this is invalid as #sinx# can only have values between #1 and -1#.

Therefore, there is no solution.