In the reaction between sodium oxide and water, what mass of sodium oxide will be needed to produce 5.90g of sodium hydroxide ?

1 Answer
Phiri
Apr 29, 2018

#5.25"g"#

Explanation:

First we need our balanced equation.

#Na_2O + H_2O rarr 2NaOH#

For this problem, we need to work backwards, finding moles of #2NaOH#, then how many moles of #Na_2O# was required to make the #2NaOH#, then convert that to grams.

First we find how many moles of #2NaOH# are in 5.90g.

#5.90"g" * "1mol"/"40.00g" = .148"g"#

Then we check how many moles of #Na_2O# were required to produce it.

#0.148"mol "Na_2O" * "1mol Na_2O"/"2"mol 2NaOH" = 0.0740"mol"#

Then convert the moles to grams.

#"0.0740mol" * 70.99"g/mol" = 5.25"g"#

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