How do you write the function in standard form $y=-6(x-2)^2-9$ ?

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Answer 1 · 2018-04-29T04:37:43

$y = -6x^2 + 24x - 33$

$y = -6(x-2)^2 - 9$

To write an equation in standard form, it has be in the form $y = ax^2 + bx + c$ . To get this, let's distribute and simplify.

$y = -6(x-2)(x-2) - 9$

Expand $(x-2)(x-2)$
$y = -6(x^2 - 2x - 2x + 4) - 9$

Combine like terms:
$y = -6(x^2 - 4x + 4) - 9$

Multiply out the $-6$ :
$y = -6x^2 + 24x - 24 - 9$

Combine like terms:
$y = -6x^2 + 24x - 33$

Hope this helps!

How do you write the function in standard form y=-6(x-2)^2-9y=-6(x-2)^2-9?