How do you solve #5( c - 96) = - 5#?

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Answer 1 · 2018-04-29T17:56:08

#=>c = 95#

We start with:

#5(c-96) = -5#

We distribute the LHS:

#(5)(c) + (5)(-96) = -5#

We simplify:

#5c - 480 = -5#

We add #480# to both sides:

#5c = 475#

We divide both sides by #5#:

#=>c = 95#