Question

Can you help me? `lim(x,y)rarr(0,0)(sin(x^2+y^2)/(2x^2+2y^2))`

Answer 1

`1/2`

Explanation:

.

We know that:

`Lim_(theta->0)sintheta/theta=1`

Let `theta=x^2+y^2`

`Lim_((x,y)->(0,0))((sin(x^2+y^2)/(x^2+y^2))/2)=1/2`