If f(x) = x^3-x what is the average rate of change of f(x) over the interval [1,5]?
1 Answer
Apr 30, 2018
Explanation:
#"the average rate of change of "f(x) " over an"#
#"interval between 2 points is the slope of the secant"#
#"line connecting the 2 points"#
#"It is calculated as"#
#(f(b)-f(a))/(b-a)#
#"where a, b is the closed interval "[a,b]#
#"here "[a,b]=[1,5]#
#f(b)=f(5)=5^3-5=120#
#f(a)=f(1)=1-1=0#
#rArr(120-0)/(5-1)=120/4=30#
