Question

Given the function f defined by f(x) =(2x-2)/(x^2+x-2) for what values of x is f(x) discontinuous?

Answer 1

`f` is discontinuous at `-2` and at `1`

Explanation:

A rational function (like this one) is discontinuous where it is undefined.
That happens where the denominator is `0`

`x^2+x-2=0`

`(x+2)(x-1)=0`

`x=-2` OR `x=1`