Question

How many molecules, carbon atoms, moles of molecules, and moles of atoms in 5 moles of CaCO3?

This is what the question says:
5.0 moles of CaCO3 contain
_ molecules (number)
carbon atoms (number)
_ moles of molecules (number)
moles of atoms (number).

I know that 1 mole contains 6.022 10^23 atoms, so in total there will be 56.022*10^23 atoms in the 5 moles.
How do you find the above^^, especially seeing as CaCO3 is an ionic compound?
Thankss

Answer 1

`30.11*10^23` molecules `CaCO_3`
`30.11*10^23` C atoms
5 moles of `CaCO_3`
25 moles of atoms

Explanation:

1 mol=`6.022*10^23` particles, so:

5 mol `CaCO_3` =`5*6.022*10^23` = `30.11*10^23` molecules

In each mole of `CaCO_3`, there is one carbon atom, so there is an equivalent amount of moles and carbon atoms. There are:

`30.11*10^23` carbon atoms

Moles of molecules is a given, there are 5.

There are 5 atoms/formula unit, so there are 5 moles * 5 atoms/unit =25 moles of atoms