How do you simplify #\sqrt { 49a ^ { 15} }#?

1 Answer
May 1, 2018

#7a^7.5#

Explanation:

As #49=7*7=7^2#,
#sqrt49 = 7#
And #sqrt (a^15)= sqrt(a^14)*sqrta=a^7sqrta=a^7.5#
Multiplying the two, we get
#sqrt (49a^15)= 7a^7sqrta=7a^7.5#
I think both #7a^7sqrta# and #7a^7.5# would be acceptable, and I cannot see any more simplification than this.