Question

How do you simplify `\sqrt { 49a ^ { 15} }`?

Answer 1

`7a^7.5`

Explanation:

As `49=7*7=7^2`,
`sqrt49 = 7`
And `sqrt (a^15)= sqrt(a^14)*sqrta=a^7sqrta=a^7.5`
Multiplying the two, we get
`sqrt (49a^15)= 7a^7sqrta=7a^7.5`
I think both `7a^7sqrta` and `7a^7.5` would be acceptable, and I cannot see any more simplification than this.