How do you make #t# the subject of the formula #2(d-t) = 4t+7#?

1 Answer

#t=(2d-7)/6#

Explanation:

Expand the left hand side first using the distributive method #a(b+c)=ab+ac#.

#2(d-t)# is #2 xxd =2d# and #2 xx -t =-2t#

#2d-2t=4t+7quadquad# now take all the t's to the right hand side
#2d=6t+7quadquadquad# take the +7 to the left hand side
#2d-7=6tquadquadquad# divide both sides by 6 to get t on its own

#(2d-7)/6=t#

You could go one further and separate the single fraction on the left hand side into two fractions and simplify where possible

#(2d)/6 -7/6=t#

#d/3-7/6=t# or even turn the improper fraction to a mixed number

#d/3-1 1/6=t#