Question

How many chloride ions are there in 4.50 mol of aluminum chloride?

Answer 1

`"13.5mol" (Cl^+)`

Explanation:

Aluminum Chloride is `AlCl_3`.

For every moles of `AlCl_3`, you have 3 moles of `Cl^+` ions.

Therefore:

`"4.50mol" (AlCl_3) * ("3mol" (Cl))/("1mol" (AlCl_3)) = "13.5mol" (Cl)`