What are two numbers such that the greater number is 75% more than the lesser number?

2 Answers
May 2, 2018

Any two numbers of the form #x and 7/4x#. If we limit them to be natural numbers, the smallest solution is #4 and 7.#

Explanation:

Let the lesser number be #x.#
The greater number is #75%# more than #x#. So, it must be:
# = x + (75/100)x#
#= x + 3/4x#
#= 7/4x#

Thus the answer is any two numbers of the form#(x, 7/4x).# Setting #x = 4# makes both a natural number. So, the smallest answer(if #x in N#) is #(4, 7)#.

May 2, 2018

#x = 1, y = 1.75#
#x = 2, y = 3.5#
#x = 4, y = 7#

These are examples, there are an infinite set of numbers you can use.

Explanation:

Let's call y the larger number, and x the lesser.

#y = 1.75x#

From here you can insert any number x, and get a y value that satisfies your problem.

Examples:
#x = 1, y = 1.75#
#x = 2, y = 3.5#
#x = 4, y = 7#