2HCl + CaCO3 = CaCl2 + H2O + CO2. how many mL of CO2 at 18 celsius and 715 mm Hg can be generated from 87 grams of calcium carbonate?
1 Answer
May 2, 2018
Approx.
Explanation:
We address the stoichiometric equation...
And thus moles of carbonate is equivalent to the moles of
And so
And thus we need to find the volume of a
Multiply by 1000 to get an answer in