How do you find the equation of the line tangent to #f(x)=2x^2# at x=-1?
1 Answer
May 3, 2018
Explanation:
#"we require the slope m and a point on the line to"#
#"obtain the equation of tangent"#
#•color(white)(x)m_(color(red)"tangent")=f'(-1)#
#rArrf'(x)=4xrArrf'(-1)=-4#
#f(-1)=2(-1)^2=2rArr(-1,2)" is point on line"#
#rArry-2=-4(x+1)#
#rArry=-4x-2larrcolor(red)"equation of tangent"#
