Show that #sin^7 x + cos^7 x < 1# if #0 < x < frac{\pi}{2}#. Please explain in words how to calculate this?

1 Answer
May 4, 2018

When #x# is a non zero acute angle, both #sin x # and #cos x# are positive numbers smaller than one. For such numbers, higher powers are smaller than lower ones (since each time you raise the power you are multiplying by a number smaller than one). Thus #sin^7x# and #cos^7x# are smaller than #sin^2x# and #cos^2x#, respectively, since the latter add up to 1, the sum of the seventh powers must be smaller than 1.